A line has slope –5(over)3 . Through which two points could this line pass? (1 point)
(12, 13), (17, 10)
(16, 15), (13, 10)
(0, 7), (3, 10)
(11, 13), (8, 18)
The points of the line that has a slope of -5 over 3 is (11,13) (8, 18). This can be computed using the formula of finding the slope of a line which m = y2-y2 over x2-x1. This is computed as follows:
m = 18-13 over 8 - 11 m= 5 over -3 or simplified to m= -5 over 3