sweeKa9rlapingsabit
sweeKa9rlapingsabit sweeKa9rlapingsabit
  • 07-06-2016
  • Mathematics
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The point (5/13, y) in the fourth quadrant corresponds to angle theta on the unit circle. Find sec theta and cot theta

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HomertheGenius
HomertheGenius HomertheGenius
  • 17-06-2016
cos (theta) =[tex] \frac{5}{13} [/tex] sec (theta) = [tex] \frac{1}{cos(theta)} = \frac{1}{ \frac{5}{13} }= \frac{13}{5} [/tex] sin(theta)=[tex] \sqrt{1- cos^{2}(theta) } = \sqrt{1 - \frac{25}{169} } = \sqrt{ \frac{144}{169} }=- \frac{12}{13} [/tex] cot(theta)=[tex] \frac{cos(theta)}{sin(theta}= \frac{ \frac{5}{13} }{ \frac{-12}{13} }= \frac{-5}{12} [/tex]
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