Answer:
It takes 1 second to drop 26.4 meters, for acceleration due to gravity, the acceleration would double from the meters and would be 52.8 m/s^2.
Is there more information above question 4?
Explanation:
Δx = v₀ t + ½ at²
v₀ = 0, so:
Δx = ½ at²
Solving for a:
2Δx = at²
a = 2Δx / t²
Plug in any point:
a = 2 (26.4 m) / (1.0 s)² = 52.8 m/s²
