Up to multiples, if you're given the roots you can write the polynomial by multiplying several parenthesis in the form
[tex](x-x_0)[/tex]
where [tex]x_0[/tex] is a root. So, in your case, you have
[tex]f(x) = a(x+6)(x+5)(x+1)[/tex]
We can fix the parameter a by imposing f(0)=60:
[tex]f(0)=a(0+6)(0+5)(0+1)=30a=60\iff a=2[/tex]
So, your polynomial is
[tex]f(x) = 2(x+6)(x+5)(x+1)=2x^3+24x^2+82x+60[/tex]
