Yokaikiki Yokaikiki
  • 07-10-2019
  • Mathematics
contestada

Help me please!
[tex]16x ^{0} + 2x ^{2} \times y ^{ - 1} [/tex]
x=2 and y=4
Evaluate
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Respuesta :

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  • 07-10-2019

Answer:

18

Step-by-step explanation:

Evaluate (2 x^2)/y + 16 x^0 where x = 2 and y = 4:

16 x^0 + (2 x^2)/y = 16×2^0 + (2×2^2)/4

2/4 = 2/(2×2) = 1/2:

16×2^0 + 2^2/2

Combine powers. 2^2/2 = 2^(2 - 1):

16×2^0 + 2^(2 - 1)

2 - 1 = 1:

16×2^0 + 2

2^0 = 1:

16×1 + 2

16 + 2 = 18:

Answer:  18

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