Clover7369 Clover7369
  • 08-08-2019
  • Chemistry
contestada

At a certain temperature, the solubility of zinc(I) chromate is (7.0x10^-5) M. What is the Ksp?

Respuesta :

gbustamantegarcia054 gbustamantegarcia054
  • 16-08-2019

Answer:

Ksp = 4.9 E-9

Explanation:

  • S = 7.0 E-5 M
  •        ZrCrO4 ↔ Zr²+  +  CrO4²-

solubility:       S            S             S

⇒ Ksp = [ Zr²+ ] * [ CrO4²- ]

⇒ Ksp = S * S = S²

⇒ Ksp = ( 7.0E-5)²

⇒ Ksp = 4.9E-9

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