Answer:
Step-by-step explanation:
Put the equation in the form ax+by+c=0:
[tex]y\sqrt{3} =8x+\sqrt{3} \\=>8x-\sqrt{3} y+\sqrt{3} =0[/tex]
Check the solutions:
[tex](0,-1)[/tex]:
[tex]8(0)-\sqrt{3} (-1)+\sqrt{3} =2\sqrt{3}[/tex]
So this is not a solution.
([tex](\sqrt{3} ,9)[/tex]:
[tex]8\sqrt{3} -9\sqrt{3} +\sqrt{3} =0[/tex]
So this is a solution
