Answer:
There are 2 solutions to this equation
[tex]x=-\frac{1}{4} +i\frac{\sqrt{19} }{4} ,x=-\frac{1}{4} -\frac{\sqrt{19} }{4}[/tex]
Step-by-step explanation:
for a quadratic equation of the form ax^2 + bx + c = 0 the solutions are
[tex]x_{1,2}=\frac{-b±\sqrt{b^{2}-4ac } }{2a}[/tex]
[tex]x=\frac{-2+\sqrt{2^{2}-4.4.5 } }{2.4} :-\frac{1}{4}+ i\frac{\sqrt{19} }{4} \\x=\frac{-2-\sqrt{2^{2}-4.4.5 } }{2.4} :-\frac{1}{4} -i\frac{\sqrt{19} }{4}[/tex]
brainiest plz
