For this case we have that, by definition, the volume of the cylinder is given by:
[tex]V = \pi * r ^ 2 * h[/tex]
Where:
h: It's the height
A: It's the radio
We have to:
[tex]h = 15\\r = 12[/tex]
Substituting:
[tex]V = \pi * (12) ^ 2 * 15\\V = \pi * 144 * 15\\V = 2160 \pi \ units ^ 3[/tex]
Answer:
Option B
