[tex]d[/tex] stands for distance.
[tex]
d(J, K)=\sqrt{(7-2)^2+(8-4)^2}=\sqrt{25+16}\approx6.4
[/tex]
d(J, L)=\sqrt{(1-2)^2+(-1-4)^2}=\sqrt{1+16}\approx4.12
[tex]d(J, K)>d(J, L)[/tex] therefore the answer is D.
