gja121100
gja121100 gja121100
  • 06-05-2019
  • Mathematics
contestada

Which is a solution for the equation log (2x-1) + log 5=1

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TaeKwonDoIsDead
TaeKwonDoIsDead TaeKwonDoIsDead
  • 06-05-2019

Answer:

[tex]x=\frac{3}{2}[/tex]

Step-by-step explanation:

When we don't have any base with "log", we assume it to have base 10.

Using the property Log M + Log N = Log(M*N), we can write:

Log (2x-1) + Log 5 = 1

Log ((2x-1)(5)) = 1

We can turn this into exponential form using  [tex]Log_{a} b=x\\a^x=b[/tex]

Thus,

[tex]10^1=(2x-1)(5)\\10=10x-5\\10+5=10x\\15=10x\\x=\frac{15}{10}=\frac{3}{2}[/tex]

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