Respuesta :

r3t40

[tex]

3i(-7+11i)=-28i+33i^2=\boxed{-33-28i}

[/tex]

choixongdong

Answer:

-33 - 21i

Step-by-step explanation:

3i (-7 + 11i)

= -21i + 33i^2                   (i^2 = -1)

= -21i + 33(-1)

= -33 - 21i

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