completelybored18
completelybored18 completelybored18
  • 10-03-2019
  • Mathematics
contestada

Find three consecutive odd numbers the product of which is 148 more than the cube of their middle number.

Respuesta :

calculista
calculista calculista
  • 19-03-2019

Answer:

   The numbers are [tex]-39,-37,-35[/tex]

Step-by-step explanation:

Let

x-----> the first odd number

x+2----> the middle odd number

x+4---> the third odd number

[tex]x(x+2)(x+4)=(x+2)^{3} +148[/tex]

[tex](x^{2}+2x)(x+4)=(x^{2}+4x+4)(x+2)+148\\x^{3}+4x^{2}+2x^{2}+8x=x^{3}+2x^{2}+4x^{2}+8x+4x+8+148\\x^{3}+6x^{2}+8x=x^{3}+6x^{2}+12x+156\\8x=12x+156\\4x=-156\\x=-39[/tex]

The numbers are

[tex]x=-39[/tex]

[tex]x+2=-39+2=-37[/tex]

[tex]x+4=-39+4=-35[/tex]

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