ks2021 ks2021
  • 08-03-2019
  • Mathematics
contestada

PLEASE HELP WITH THIS ONE! WORTH A LOT OF MY GRADE

PLEASE HELP WITH THIS ONE WORTH A LOT OF MY GRADE class=

Respuesta :

thapatezendra2074 thapatezendra2074
  • 08-03-2019

here you can see the answer.

Ver imagen thapatezendra2074
Answer Link
Gyzmo
Gyzmo Gyzmo
  • 08-03-2019

Answer:

JK = 11

Step-by-step explanation:

ΔJKL = ΔJML by the ASA theorem, so JK = JM.

3x - 16 = 2x - 7

plus 16 both sides

3x = 2x + 9

minus 2x both sides

x = 9

plug in x = 9 for 3x - 16

3(9) - 16 = 27 - 16 = 11

JK = 11

Answer Link

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