freemybrothers4 freemybrothers4
  • 07-03-2019
  • Mathematics
contestada

Solve 7x + 1 < 4(x - 2). {x | x < 3} {x | x > 3} {x | x > -3} {x | x < -3}

Respuesta :

CharlieBrown2002
CharlieBrown2002 CharlieBrown2002
  • 07-03-2019

Hello there!

Answer:

[tex]\boxed{D. x<-3}[/tex]

Step-by-step explanation:

Distributive property: a(b+c)=ab+ac

First, you expand.

4(x-2)=4x-8

7x+1<4x-8

Subtract by 1 both sides of an equation.

7x+1-1<4x-8-1

Add/Subtract numbers from left/right.

8+1=9

7x<4x-9

Then, you subtract by 4x both sides of an equation.

7x-4x<4x-9-4x

Simplify equation.

3x<-9

Divide by 3 both sides of an equation.

3x/3<-9/3

Divide numbers from left/right.

-9/3=-3

x<-3 is the final answer.

Hope this helps!

Thanks!

-Charlie

Have a nice day! :)

:D

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