[tex]\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ V=1767.1 \end{cases}\implies 1767.1=\cfrac{4\pi r^3}{3}\implies 5301.3=4\pi r^3 \\\\\\ \cfrac{5301.3}{4\pi }=r^3\implies \sqrt[3]{\cfrac{5301.3}{4\pi }}=r\implies 7.4999\approx r[/tex]
