Answer:
D. [tex]\frac{x-1}{x^2+3x+2}}[/tex]
Step-by-step explanation:
The given expression is;
[tex]\frac{x}{x^2+3x+2}-\frac{1}{(x+2)(x+1)}[/tex]
This is the same as;
[tex]\frac{x}{(x+2)(x+1)}-\frac{1}{(x+2)(x+1)}[/tex]
The denominators are the same.
Subtract the numerators and write one denominator;
[tex]\frac{x-1}{(x+2)(x+1)}}[/tex]
Rewrite to get;
[tex]\frac{x-1}{x^2+3x+2}}[/tex]
