Answer:
g(x) = 0 for x = 2 and x = 4.
Step-by-step explanation:
[tex]g(x)=x^2-5x+6\\\\g(x)=0\iff x^2-5x+6=0\\\\x^2-3x-2x+6=0\\\\x(x-3)-2(x-3)=0\\\\(x-3)(x-2)=0\iff x-3=0\ \vee\ x-2=0\\\\x-3=0\qquad\text{add 3 to both sides}\\\\\boxed{x=3}\\\\x-2=0\qquad\text{add 2 to both sides}\\\\\boxed{x=2}[/tex]
