Since child is revolving on the merry go round
So here speed of child is 2 m/s and its radius is given as 1.5 m
Now during revolution of wheel the acceleration of child is known as centripetal acceleration
It is given as
[tex]a = \frac{v^2}{R}[/tex]
[tex]a = \frac{2^2}{1.5}[/tex]
[tex]a = \frac{8}{3} m/s^2[/tex]
so here acceleration of child will be 2.67 m/s^2
