yuritzyarteaga1 yuritzyarteaga1

09-12-2018
Mathematics

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Altherra Altherra

09-12-2018

Volume of a cone =
[tex] \frac{1}{3} \pi{r}^{2} h[/tex]

[tex] \frac{1}{3} \pi \times {4}^{2} \times 9 = 48\pi[/tex]

8138.88 / 48pi = 53.972

Maximum cones that.can be filled= 53

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