y = - [tex]\frac{1}{4}[/tex] x + 3
the equation of a line in slope-intercept form is
y = mx +c ( where m is the slope and c the y-intercept )
rearrange x + 4y = 12 into this form
subtract x from both sides
4y = - x + 12 ( divide all terms by 4 )
y = - [tex]\frac{1}{4}[/tex] x + 3 ← in slope-intercept form
