the coordinates of the points of intersection of the graph of y=13−x with the axes
Given equation is y=13-x
x axis is x=0
y axis is y=0
Plug in the value of x =0 and find out y
y = 13 - x
y = 13 - 0 = 13
Plug in the value of y=0 and find out x
0 = 13 - x
x= 13
So coordinate axis
x= (13,0)
y= (0,13)
Base of the triangle is x=13
Height of the triangle is y= 13
Area of the triangle = [tex]\frac{1}{2} * base * height[/tex]
= [tex]\frac{1}{2} * 13 * 13[/tex] = 84.5
Area of the triangle = 84.5
