Yuii
Yuii Yuii
  • 08-09-2018
  • Mathematics
contestada

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Simplify.

PLEASE HELP ASAP CORRECT ANSWER ONLY PLEASE Simplify class=

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gmany
gmany gmany
  • 08-09-2018

[tex]i=\sqrt{-1};\ i^2=-1\\\\-2i\sqrt{-12}=-2i\sqrt{(-1)(12)}=-2i\sqrt{-1}\cdot\sqrt{12}\\\\=-2i\cdot i\sqrt{4\cdot3}=-2i^2\sqrt4\cdot\sqrt3=-2(-1)\cdot2\sqrt3\\\\=4\sqrt3\\\\\text{Used:}\ \sqrt{a\cdot b}=\sqrt{a}\cdot\sqrt{b}[/tex]

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