Respuesta :

kenmyna

The moles of solute particles that are present in 100.0 ml of 2.50M (NH4)3Po4 is 0.25 moles

calculation

moles=volume in liters x molarity

volume in liters=100/1000= 0.1L

molarity=2.50M

moles is therefore= 2.50 x0.1=0.25moles