Respuesta :

lesliekolleroxrkcf
x²=3x+3
x²-3x-3=0. have to get 0 on right first
identify a,b,c. a is 1, b is -3, c is -3
now plug in to the quadratic formula...

x = -b±√(b²-4*a*c) / 2a

x = -(-3) ± √((-3)²-4*1*(-3)) / (2*1)

x= 3 ± √(9- -12) / 2

x=( 3 ± √21) /2

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