Respuesta :

konrad509
[tex]2x^2+16x-8=0\\ x^2+8x-4=0\\ x^2+8x+16-20=0\\ (x+4)^2=20\\ x+4=\sqrt{20} \vee x+4=-\sqrt{20}\\ x=-4+2\sqrt5 \vee x=-4-2\sqrt5[/tex]
1018706pet

Answer:

c.

Step-by-step explanation:

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