Respuesta :

altavistard
Combine like terms:  −4z+31≥17z+23 becomes 31 ≥ 21z + 23, and 31 ≥ 21z + 23 becomes 8 ≥ 21z.

To solve for z, divide both sides of this inequality by 21:  8/21 ≥ z, or z ≤ 8/21.
st4rgrl
The answer is [tex] \frac{8}{21} [/tex]≥z.

-4z+31≥17z+23
+4z      +4z
----------------------
       31≥21z+23
      -23       -23
-----------------------
       8≥21z
      ---  -----
      21   21
     
[tex] \frac{8}{21} [/tex]≥z

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