ppatel345
ppatel345
09-06-2018
Mathematics
contestada
REPLY BACK PLEASE.. HAVE NO CLUE AT ALL
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lizzyness
lizzyness
09-06-2018
Go on a calculator
cosine=Adjacent/Hypotenuse
Cosine=6/ 3 the square root of 5
reduce to 1/square root of 5 which is your answer...so the answer is B)
Hope this helps!!
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gustanika
gustanika
10-06-2018
sine = [tex] \dfrac{\text{opposite}}{\text{hypotenuse}} [/tex]
sine = [tex] \dfrac{3}{3 \sqrt{5}} [/tex]
sine = [tex] \dfrac{1}{ \sqrt{5} } [/tex]
Cosecant is reciprocal of sine, that means
cosecant = [tex] \dfrac{1}{\text{sine}} [/tex]
input the value of sine
cosecant = [tex] \dfrac{1}{ \dfrac{1}{ \sqrt{5} } } [/tex]
cosecant = [tex]1: \dfrac{1}{ \sqrt{5}}[/tex]
cosecant = [tex]1 \times \dfrac{ \sqrt{5} } {1}[/tex]
cosecant = [tex] \sqrt{5} [/tex]
The answer is first option
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