For this case we have a square whose sides are known and equal to 60 ft.
We want to find the diagonal of the square.
For this, we use the Pythagorean theorem.
We have then:
[tex]d^2 = 60^2 + 60^2
d = \sqrt{60^2 + 60^2}
d = \sqrt{3600 + 3600}
d = \sqrt{2*3600}
d = 60\sqrt{2}
[/tex]
Answer:
from home to second base it is about:
[tex]d = 60\sqrt{2} feet[/tex]
