Answer:
[tex]\large\boxed{i^{41}=i}[/tex]
Step-by-step explanation:
[tex]i=\sqrt{-1}\\\\i^2=-1\\\\(-1)^2=1\\\\\text{Use}\ a^n\cdot a^m=a^{n+m}\ \text{and}\ (a^n)^m=a^{nm}:\\\\i^{41}=i^{40+1}=i^{40}\cdot i=i^{2\cdot20}\cdot i=(i^2)^{20}\cdot i=(-1)^{20}\cdot i=1\cdot i=i[/tex]
