Answer:
(-6,0) and (3,0)
Step-by-step explanation:
we have the function [tex]f(x)=(x+6)(x-3)[/tex] and the x-intecept of the function will be when y=0 then:
[tex]f(x)=(x+6)(x-3)\longrightarrow 0=(x+6)(x-3)[/tex]
Then the result will be 0 when x=-6 or x=3
