ADYSCSCANALES ADYSCSCANALES
  • 09-10-2022
  • Mathematics
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⇐|A₁|==(|2!|) ∧ |B₁|==(|5!|) ⟹⇐ |A₁|==(|2!|) ∧ |B₁|==(|5!|) ⟹ |C₁|==(|122|) ∧⇐ |A₁|+|B₁| = {|2| == {[2(1)]} + {|120| == [[[[|5|(|4|)](|3|)](|2|)](|1|)] ∨ [[[|20
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